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keisanHigh-precision calculations for everyday life and work

Complete elliptic integral of the 2nd kind E(k)

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Compute complete elliptic integral of the 2nd kind E(k).
\(E(k)={\large\int_{\small 0}^{\frac{\pi}{2}}\sqrt{1-k^2sin^2\theta}}d\theta\)
k 
-1≦k≦1
\(\normalsize Complete\ elliptic\ integral\\ \hspace{120px} of\ the\ 2nd\ kind\ E(k)\\ (1)\ E(k)={\large\int_{\small 0}^{\frac{\pi}{2}}\sqrt{1-k^2sin^2\theta}}d\theta\\ \hspace{60px}={\large\int_{\small 0}^{\small 1}\sqrt{\frac{1-k^2t^2}{1-t^2}}}dt\\\)

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