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Incomplete elliptic integral of the 1st kind F(φ,k)

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Calculates the incomplete elliptic integral of the 1st kind F(φ,k). For the substitution x=sin(φ), use F(x,k).
\(F(\phi,k)={\large\int_{\small 0}^{\small\phi}\frac{d\theta}{\sqrt{1-k^2 \sin^2\theta}}}\)
φ 
k 
-1≦k≦1
\(\normalsize Incomplete\ elliptic\ integral\\ \hspace{120px} of\ the\ 1st\ kind\ F(\phi,k)\\ (1)\ F(\phi,k)={\large\int_{\small 0}^{\small\phi}\frac{d\theta}{\sqrt{1-k^2 \sin^2\theta}}}\\ \hspace{70px}={\large\int_{\small 0}^{\small x}\frac{dt}{\sqrt{(1-t^2)(1-k^2t^2)}}}\ ,\hspace{10px}x= \sin\phi\\\)


・If x = sin(φ), you can use the related library F(x, k).

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