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Incomplete elliptic integral of the 2nd kind E(φ,k)

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Calculates the incomplete elliptic integral of the 2nd kind E(φ,k). For the substitution x=sin(φ), use E(x,k).
\(E(\phi,k)={\large\int_{\small 0}^{\small\phi}\sqrt{1-k^2 \sin^2\theta}}d\theta\)
φ 
k 
-1≦k≦1
\(\normalsize Incomplete\ elliptic\ integral\\ \hspace{120px} of\ the\ 2nd\ kind\ E(\phi,k)\\ (1)\ E(\phi,k)={\large\int_{\small 0}^{\small\phi}\sqrt{1-k^2 \sin^2\theta}}d\theta\\ \hspace{75px}={\large\int_{\small 0}^{\small x}\sqrt{\frac{1-k^2t^2}{1-t^2}}}dt\ ,\hspace{30px}x= \sin\phi\\\)



・If x = sin(φ), you can use the related library E(x, k).

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