You are using the new UI (Beta).Return to the original UI

This page has been automatically translated by machine translation. Please note that translations may not be entirely accurate.

keisanHigh-precision calculations for everyday life and work

Tidal forces of the Moon and the Sun

Manage Bookmarks
Calculate the gravitational and tidal forces of the Moon and the Sun, and determine the ratio relative to the Moon (at perigee).
Lunar mass
kg
Distance to the Moon
km,
Eccentricity
Solar mass
kg
Distance from the Sun
km,
Eccentricity
Earth’s mass
kg,
Radiuskm
Gravitational force is inversely proportional to the square of the distance, while tidal force is inversely proportional to the cube of the distance.
The Moon’s tidal force is approximately 2.2 times that of the Sun’s.
Due to the Moon’s elliptical orbit, the ratio of tidal forces at perigee to apogee is approximately 1.4.

\(\normalsize Gravitational\ force\hspace{30px}F={\large\frac{GMm}{r^2}}\\ Tide\ force\hspace{30px}T=-{\large\frac{dF}{dr}}R={\large\frac{2GMm}{r^3}}R\\ \hspace{110px}R:\ radius\ of\ the\ Earth\)

No customer feedback for this calculation yet.

Tidal forces of the Moon and the Sun | Keisan