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keisanHigh-precision calculations for everyday life and work

Frequency-Based e Exponential Regression

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Analyze the entered frequency distribution table using e exponential regression and plot a graph.
e Exponential Regression: y = AeBx
(Click each cell in the table below to enter data)
Data
(Table Input)
No.
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Interpreting the Correlation Coefficient r
0.7<|r|≦1 Strong correlation
0.4<|r|<0.7 Moderate correlation
  0.2 < |r| < 0.4 Weak correlation
0 ≤ |r| < 0.2 No correlation

\(\normalsize\ e{\tiny -}Exponential\ regression\\ (1)\ mean:\ \bar{x}={\large \frac{{\small \sum}{x_i}}{n}},\hspace{10px}\overline{\ln y}={\large \frac{{\small \sum}{\ln y_i}}{n}},\hspace{10px}n={\small \sum}f_i\\ (2)\ trend\ line:\ y=Ae^{Bx},\hspace{10px} B={\large\frac{Sxy}{Sxx}},\hspace{10px} A=\exp({\overline{\ln y}-B\bar{x}})\\ \\ (3)\ correlation\ coefficient:\ r=\frac{\normalsize S_{xy}}{\normalsize \sqrt{S_{xx}}\sqrt{S_{yy}}}\\ \hspace{20px}S_{xx}={{\small \sum}(x_i-\bar{x})^2 f_i}={{\small \sum} x_i^2 f_i}-n \cdot \bar{x}^2\\ \hspace{20px}S_{yy}={{\small \sum}(\ln y_i-\overline{\ln y})^2 f_i}={{\small \sum} \ln y_i^2 f_i}-n \cdot \overline{\ln y}^2\\ \hspace{20px}S_{xy}={{\small \sum}(x_i-\bar{x})(\ln y_i-\overline{\ln y}) f_i}={{\small \sum} x_i \ln y_i f_i}-n \cdot \bar{x}\overline{\ln y}\\ \)

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