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Area of solar power generation required for a lunar mass driver

Author: kekekeExecutions: 1508
TOP/Shared Formulas (Science)/Astronomy

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Calculate the area required for solar power generation for a lunar mass driver.

The lunar escape velocity (the speed required to break free from the Moon’s gravity) is 2378 [m/s].
The energy required to accelerate 1 metric ton to this speed is
1000 * 2378^2 / 2 = 2827442000 [J].

The energy from sunlight at Earth’s orbital altitude is
1,366 [W/m²], known as the solar constant. , so the annual energy is
1366 * (60*60*24*365.2422) = 43106761025.28 [J/m^2].

From these values, we can calculate the required area for solar power generation.
Conversion Efficiency
This refers to the ability to convert sunlight into electricity.
It’s said that quantum dot solar cells can reach a maximum of 0.6.
Utilization Efficiency
This is the percentage of the generated electricity that can actually be used by the mass driver.
It is a parameter that accounts for losses due to power transmission and the cooling of the electromagnetic catapult.
Annual Target Weight
This is the annual tonnage transported.
The baseline is 10 million metric tons per year for colony construction materials.
The solar power generation area is [m^2]
The length of one side is [m]

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