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Energy produced per gram of fusion fuel

Author: kekekeExecutions: 2784

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Electronvolts per atomic mass unit = Generated electronvolts / (Fuel 1 + Fuel 2);
// From 1 [kg] = 1.6605402 * 10^27 [u]
Atomic mass per gram = 10^24 / 1.6605402;
electronvolts per gram = electronvolts per atomic mass * atomic mass per gram;
// From 1 [J] = 1.60217733 / 10^19 [eV], convert to MeV
Joules per electronvolt = 1.60217733 / 10^(19-6);
// Answer
Joules per gram = electron volts per gram * joules per electron volt;
Gigajoules per gram = joules per gram / 10^9;
Atomic mass of Fuel 1
[u]D: 2.0141017778
Atomic mass of Fuel 2
[u]He3 : 3.0160293191
T : 3.0160492777
D-D : D*2 = 4.0282035556
Generated electron volts
[MeV]D-He3: 18.3
D-T: 17.6
D-D: (3.23 + 18.3) / 2 + (4.03 + 17.6) / 2 = 21.58
Energy generated from 1 g of fuel [MeV]
 [J]
 [GJ]

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