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Tensile Fracture Due to Steel Expansion Force -- STEEL-THERMAL-EXP

Author: hirocherry7312Executions: 82
TOP/Shared Formulas (Engineering)/Civil & Mechanical

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Restrained (fixed) steel generates stress due to temperature differences, requiring a restraining force; if the stress exceeds the allowable tensile strength (N/mm²), the steel will fracture.
[325,725] STEEL-THERMAL-EXPANSION-FRACTURE=STRESS
σ = α × (T2 - T1) × E
By default, steel properties: α = 0.000012/°C, T2 = 30°C, T1 = 0°C, Young = 205,000 N/mm² → σ = 73.8 N/mm²
α
/℃
T2
℃
T1
℃
Young
N/mm²
σ N/mm²
σu (N/mm²) exceeds SS400 (<400–510), SM490A (<490–610), SN490B (490–610), TMCP355 (<520–640),TMCP385 (<550–670), SA440 (<590–740), and HSA (<780–1,000), the material will fracture; therefore, calculate the resulting temperature difference.

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