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[Spiral] Temperature and Energy Differences and Enantiomer Excess Ratio (K)

Author: helixExecutions: 229
TOP/Shared Formulas (Science)/Chemistry (General)

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The Relationship Between Temperature and Energy Differences and the Enantiomer Excess Ratio (Absolute Temperature Version)
Temperature T
K
Energy difference ΔG
kJ/mol
Enantiomeric excess (ee) %
Proportion of Mirror Image A er1 %
Proportion of Mirror Image B er2 %
Mirror-image ratio er: 1 
I am performing calculations using an expression like the one below.
ee = 100 * tanh(ΔG * 1000/2/8.3144621/T);

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