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[Spiral] Temperature and Energy Differences and ee (°C) (Increased Precision)

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The Relationship Between Temperature and Energy Differences and the Enantiomer Excess Ratio (Celsius Version)
Temperature T
℃
Energy difference ΔG
kJ/mol
Enantiomeric excess (ee) %
Proportion of Mirror Image A er1 %
Proportion of Mirror Image Body B er2 %
Mirror-image ratio er: 1 
I am performing calculations using an expression like the one below.
ee = 100 * tanh(ΔG * 1000/2/8.3144621/(273.15 + T));

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