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keisanHigh-precision calculations for everyday life and work

Number of possibilities. Three dice. Sum and product of the numbers on the dice

Author: shiroeExecutions: 34

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We will calculate the number of cases.
Consider an experiment in which three distinguishable dice are rolled.

For the sum and product of the numbers on the dice,
we will examine the number of cases where
the result falls within the range of integers from n0 to n1,
and the number of cases where the result is divisible by a natural number d.
The rest is for reference.
n0
(n0 < n1)
n1
(n0 < n1)
d
  (Natural Numbers to Divide By)
Number of "sums of numbers" within the range   (Let’s call it a)
Number of "products of the numbers drawn" within the range   (Let’s call it b)
The number of "sums of the numbers" divisible by d   (Let’s call it A)
The number of "products of dice rolls" divisible by d   (Let’s call it B)
(a/n)*100  %
(a/b)*100  %
(A/n) * 100  %
(B/n)*100  %
"Total Number of Cases" I Looked Up   (Let n be...)
The smallest “sum of the numbers on the dice” 
The Largest "Sum of Numbers" 
Minimum "Product of Numbers" 
The Largest "Product of Numbers" 
Digit display setting: 6 digits. Digit count can be changed. Real number calculation mode.

Reference:
6^2=36
6^3=216
6*3=18
1+1+1=3
1^3=1

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