When the x- and x'-axes coincide (the origin is shifted)
Author: shiroeExecutions: 27
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Enter t, x, y, z, v, and c.
Outputs t', x', y', and z'.
The rest is for reference only.
Outputs t', x', y', and z'.
The rest is for reference only.
| t' | [s] |
| x' | [m] |
| y' | [m] |
| z' | [m] |
| v/c | |
| (v/c)² | |
| 1-(v/c)^2 | |
| √(1-(v/c)^2) | |
| The imaginary part of √(1-(v/c)^2) |
Special Lorentz transformation.
Note the sign, the imaginary unit "i" at the end of the output field, and the "E-??" symbol.
Digit display set to 6 digits. The number of digits can be changed. Complex number calculation mode.
Note the sign, the imaginary unit "i" at the end of the output field, and the "E-??" symbol.
Digit display set to 6 digits. The number of digits can be changed. Complex number calculation mode.
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At t = 0, the origins coincide.
The form of the transformation equations is
t' = (t - (v/(c^2))x) / √(1 - (v/c)^2)
x' = (x - vt) / √(1 - (v/c)^2)
y' = y
z' = z
.
In the S reference frame, the positive direction of v is toward x = +∞.
c is the speed of light. (Input range: non-zero positive values)