An experiment involving drawing lots from two boxes
Author: shiroeExecutions: 5
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Now, assuming you drew a winning ticket, let’s calculate the conditional probability that “you drew from Box A.”
| Probability numerator | (Before simplification) (Fractional form) |
| Probability denominator | (Before simplification) (Fractional form) |
| Probability numerator | (Fraction format) |
| Probability denominator | (Fraction format) |
| Probability | (Decimal format) |
Let x be the event of “drawing a winning ticket.”
Let y be the event of “selecting Box A.”
We calculate this using P(y) = P(x ∩ y) / P(x).
Digit display set to 6 digits. Digit count can be changed. Real number calculation mode.
Let y be the event of “selecting Box A.”
We calculate this using P(y) = P(x ∩ y) / P(x).
Digit display set to 6 digits. Digit count can be changed. Real number calculation mode.
No customer feedback for this calculation yet.
There are two boxes, A and B, and each box contains a certain number of winning tickets
mixed in with losing tickets.
We will randomly select a box and draw one ticket from it.