How much time dilation occurs in the theory of relativity?
Author: abcdefg85Executions: 51
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I am calculating the passage of time relative to a stationary reference frame. This differs from what is described in the official “Theory of Relativity (Time Dilation).”
1 qs (quect second) = 0.000000000000000000000000000001 seconds
1 rs (ront second) = 0.000000000000000000000000001 seconds
1 ys (yocto-second) = 0.000000000000000000000001 seconds
1 zs (zepto-second) = 0.000000000000000000001 seconds
1 as (attosecond) = 0.000000000000000001 seconds
1 fs (femtosecond) = 0.000000000000001 seconds
1 ps (picosecond) = 0.000000000001 seconds
1 ns (nanosecond) = 0.000000001 seconds
1 µs (microsecond) = 0.000001 seconds
1 ms (millisecond) = 0.001 seconds
1 rs (ront second) = 0.000000000000000000000000001 seconds
1 ys (yocto-second) = 0.000000000000000000000001 seconds
1 zs (zepto-second) = 0.000000000000000000001 seconds
1 as (attosecond) = 0.000000000000000001 seconds
1 fs (femtosecond) = 0.000000000000001 seconds
1 ps (picosecond) = 0.000000000001 seconds
1 ns (nanosecond) = 0.000000001 seconds
1 µs (microsecond) = 0.000001 seconds
1 ms (millisecond) = 0.001 seconds
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Calculate how much time has elapsed for the moving object relative to itself.