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The graph of 1/(1+x^2) (x=[0,1]) and a circle

Author: hidekichi45Executions: 101
TOP/Shared Formulas (Math)/Advanced Math

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For both y = 1/(1 + x²) and the equation of a circle, the integral over the interval x = [0, 1] is π/4 (1/4 of a circle), so the values are equal.
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