Composition of unit fractions (two terms). Inverse Egyptian calculation.
Author: shiroeExecutions: 23
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Enter A and B.
Enter natural numbers greater than or equal to 2 for A and B.
If there is a natural number C that serves as the denominator on the left-hand side, the "Result" field in the output section will display 1.
Also display the natural number that serves as the denominator C on the left-hand side.
If there is no natural number that serves as the denominator C on the left-hand side, display 0 in the “Result” field.
In this case, do not display the number that serves as the denominator C on the left-hand side.
(Note: Although C = 1 and 1/1 = 1, 1/C is not considered a unit fraction.)
Enter natural numbers greater than or equal to 2 for A and B.
If there is a natural number C that serves as the denominator on the left-hand side, the "Result" field in the output section will display 1.
Also display the natural number that serves as the denominator C on the left-hand side.
If there is no natural number that serves as the denominator C on the left-hand side, display 0 in the “Result” field.
In this case, do not display the number that serves as the denominator C on the left-hand side.
(Note: Although C = 1 and 1/1 = 1, 1/C is not considered a unit fraction.)
| Verdict | (C could not be found = 0, found = 1) |
| Denominator C | (1/A) + (1/B) = 1/C |
Digit display setting: 50 digits. Digit count can be changed. Real number calculation mode.
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This relates to Egyptian arithmetic.
It is the inverse of unit fraction decomposition.
Let the form of the expression be (1/A) + (1/B) = 1/C. (/ is the division symbol.)
The value of each numerator is 1.
A, B, and C are the denominators. A and B are known, and C is the unknown to be found.
A, B, and C are all natural numbers greater than or equal to 2.
A and B are distinct natural numbers.