Expand the expression (result will be a quadratic expression)
Author: shiroeExecutions: 13
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The default value for P in the input field is set to 1.
Enter P, a, and b (please do not leave any fields blank).
First, the program outputs j2, j1, and j0 in a form where P is not distributed.
It then distributes P and outputs k2, k1, and k0 as well.
Enter P, a, and b (please do not leave any fields blank).
First, the program outputs j2, j1, and j0 in a form where P is not distributed.
It then distributes P and outputs k2, k1, and k0 as well.
| j2 | (Before distribution) |
| j1 | (Before distribution) |
| j0 | (Before distribution) (Constant term) |
| (After distribution) | |
| (After distribution) | |
| (After distribution) (Constant term) |
Digit display set to 50 digits. Digit count can be changed. Complex number calculation mode.
Please be careful not to omit the negative sign.
In the output field, please pay attention to the imaginary unit i.
memo:
p(x+a)(x+b) = p{x^2 + (a+b)x + ab}
= px^2 + p(a+b)x + pab
Please be careful not to omit the negative sign.
In the output field, please pay attention to the imaginary unit i.
memo:
p(x+a)(x+b) = p{x^2 + (a+b)x + ab}
= px^2 + p(a+b)x + pab
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Here, we consider the case where the result is a quadratic expression.
The form of the expression is
P(x+a)(x+b) = P(j2x^2 + j1x + j0)
Distributing P,
we get
= k2x^2 + k1x + k0
.Expand the left-hand side into the right-hand side.
The numbers to the right of the letters j and k are subscripts that correspond to the degree of x.
(j0 and k0 are constant terms.)